NEET Study Notes for Laws of Motion - Newton's laws of motion are the three statements formulated by Isaac Newton that serve as the foundation of classical mechanics and explain the relationship between forces acting on a body and the motion of the body. Candidates can expect at least 1 question from this unit. Some of the important topics from this section include- Laws of Motion, Friction, Dynamics of Circular Motion.
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Topic | Sub-topics |
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Laws of Motion |
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Terms | Formulas |
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Force | mass acceleration (F= ma) |
Newtons Second Law of Motion | F= ma (mass acceleration) |
Newtons Third Law of Motion | F1= -F2 |
Momentum | Mass Velocity i.e p=mv |
Impulse | I = F • Δ t |
Friction | F = μN |
Centripetal Force | F = mv2/r |
Newtons First Law of Motion states that a body continues to be in its state of rest or of uniform motion in a straight line unless compelled by some external force to act otherwise.
Newtons Second Law of Motion describes the quantitative changes that a force can produce on the motion of an object.
Impulse is a term that quantifies the overall effect of a force acting over time. It is denoted by symbol J and expressed in Newton Seconds. We assume that force is constant over time. Impulse is a vector quantity.
For a constant force, J=F⋅Δt
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In order to understand equilibrium of concurrent forces, we must first understand what equilibrium means. Equilibrium is defined as a position of “ no acceleration”. This means that the total of all forces acting on a body is zero
There are two main types of equilibrium :
Example- If a block is resting on a floor and two forces of 5N each are acting on the side. In this situation, the forces would cancel each other out resulting in the net force on the block being zero. The block here is at rest due, thus it would in static equilibrium.
Example- A common example for Dynamic Equilibirum is when a block is attecahed to a spring under the influence of Simple Harmonic Motion (S.H.M.). Here the net force acting on the body is zero, but the velocityof the body is maximum, this will result in a state of Dynamic Equilibrium.
Newtons Third Law of Motion states that there is an equal and opposite reaction, for every action.
As per the third law, the table also applies an equal and opposite force to the book. This explains that when there is no net force acting on a body or if the forces are precisely balanced by contrary forces, the body does not accelerate and is said to be in equilibrium.
Example: Car accelerates forward because the ground pushes forward on the drive wheels, in reaction to the drive wheels pushing backward on the ground.
A system is said to be isolated when no external force acts on it. For such isolated systems, (P=mv) is constant i.e. conserved.
The linear momentum is defined as
.....(1)
Where v= velocity of the body, whose mass is m. The direction of P is same as the direction of velocity of the body as it is a vector quantity. From Netwons Second Law
I.e time rate of change in the momentum of the body is equal to total external force applied to the body
If or = constant .....(3)
This is called Law of Conservation of Momentum.
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Friction is defined as an opposing force which comes into existence when two surfaces are in contact with each other and try to move relative to one another.
is friction which is experienced when there is no relative motion between the object and the surface.The coefficient of static friction is a scalar quantity and is denoted as μs
μs = F /N
Where
μs = coefficient of static fiction
F=static frictional force
Kinetic Friction is the friction present between two or more objects that are in motion with respect to each other. The Kinetic Friction equation can be written as :
Force of Kinetic Friction =(coefficient of Kinetic Friction)(normal force)
Fk= μk η
Where ,
Fk =force of Kinetic Friction
μk = coefficient of Kinetic Friction
η= normal force
The force which resist the motion of a rolling body on a surface is known as rolling friction. With the increase in smoothness, the force of rolling friction decreases .
Rolling Friction can be expressed as a product of load and constant to a fractional power
F = kLn
The five laws of friction are:
Circular motion can be uniform as well as non uniform. The main difference between both of them is the tangential component of acceleration. If tangential component of acceleration is present, it will be non uniform circular motion whereas if the tangential component of acceleration is absent, it will be uniform circular motion
Any motion in a curved path, represents accelerated motion and requires force directed towards the center of curvature of the path. Thus we can infer from the second law of motion that
F= ma or F=
Since, there is a limit to the maximum value of fraction , for a safe turn
where μs = Coefficient of static friction
When vehicles turn on the road, they travel along a circular arc. The forces acting on vehicle are: Weight Mg, Normal reaction force N, Friction
If the road is horizontal, the first two forces are in vertical direction. Therefore the only force that provides acceleration for turning is friction. In this case, the force of fiction acts as centripetal force.
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Question: When a bus starts suddenly, the passengers are pused back. This is an example of which of the following?
Answer: When a bus starts suddenly, the passengers fall backwards due to the law of inertia of rest (Newtons first law of Motion). This is so as the body was at rest and as the bus moves abruptly , the lower body is at rest while the upper body remains in a state of rest due to which the passengers fall backward.
Question: What is the mass of an object that requires a force of 90 N to accelerate at a rate of 2.6 m/s
Answer: Force= mass x acceleration
90= m 2.6
m= 90/2.6
m= 34.6 kg
Question: Due to an acceleration of 2m/s², the velocity of body increases from 20m/s to 30 m/s in a certain period. Find the displacement (in m) of the body in that period.
Answer : 125
Given accerleration (a)= 2m/s², Final Velocity (v)= 30m/sand initial velocity (u) =20 m/s
Displacement =s
We know,
v²-u²= 2as(Equation of Motion)
s=(v²-u²)/(2×a)
s=(30²-20²)/2×2
s=500/4
s=125 cm
Question: The work to be done to increase the speed of a 0.5kg ball from 4m/s to 8m/s is:
Answer: 12J
Given that, Initial velocity (u)= 4m/s, final velocity (v)= 8m/s and
Mass(m)= 0.5 kg
Applying the work energy theorem,
Work done= Change in kinetic energy
ΔK.E= (K.E)²- (K.E)1
½m (v²-u²)
½×0.5× (8²-4²)
therefore
ΔK.E is 12J
Question: A car is running with a velocity of 20m/s and suddenly the brakes is applied to stop the car. Find the total work done to stop the car if the mass of the car is 200 kg
Answer : 40 K J
Given that, Mass of the car (m) =200 kg
Initial velocity of the car (u)= 20m/s
Final velocity of the car (v)= 0
Change in KE = Final K E- Initial K E
½m V² -½- m u² =½×200×(0-20)² = 40000J
Therefore -40 K J
Work done by all forces = -40 K J
Question: “When a hanging carpet is beaten with a stick, dust particles start coming out of it.”This phenomenon is best example of :
Answer: Newtons First Law of Motion
Since an object's inertia tends to resist any change in its state of rest or motion. When the carpet is beaten with a stick, it tends to move, however, the particles of dust are trying to resist their state of rest. This exerts a backward force on the dust particles and sets them in motion in the opposite direction. This is why the dust particles come out of the carpet.
Question: A ball of mass 2kg was initially in the hand og a girl. The girl throws the ball with 20 m/sthen find the impulse imparted to the ball
Answer : 40 kg m/s
Given that, Mass of the ball (m)= 2kg
Initial velocity of the ball
(V1) =0 and final velocity of the ball (V2)= 20 m/s
Impulse (J) imparted to the ball = P2- P1= 2×20-2×0= 40 kg m/s
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