Question: What least number must be subtracted from 1936 so that the remainder when divided by 9, 10, 15 in each case is 7?

A. 39
B. 44
C. 51
D. 129
E. 141

Answer: A

Approach Solution (1):
Step 1-Take LCM (9, 10, 15) = 90
Step 2 - Divide 1936 by 90.
1936÷90 = 21 (quotient) and 46(remainder)
Step 3 - To get 7 as remainder you must subtract 39.
As 46–39 = 7
Result:1936–39 = 189
1897÷9 = 210(quotient) + 7(remainder) 1897÷10 = 189(quotient) + 7(remainder)
Correct option: A

Approach Solution (2):
LCM = 90
1936/90 = 21 and remainder 46
If the remainder has to be ‘7’ the number to be subtracted = 46 – 7 = 39
Correct option: A

Approach Solution (3):
LCM of(9, 10, 15) = 3 × 3 × 10 = 90
1936/90, remainder = 46
Least number when is subtracted from 1936 which gives remainder 7 when divided by (9, 10, 15) is = (46 - 7) = 39
Correct option: A

“What least number must be subtracted from 1936 so that the remainder when divided by 9, 10, 15 in each case is 7?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book “GMAT Official Guide Quantitative Review”. To solve GMAT Problem Solving questions a student must have knowledge about a good amount of qualitative skills. The GMAT Quant topic in the problem-solving part requires calculative mathematical problems that should be solved with proper mathematical knowledge.

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