Question: The sum of five consecutive even numbers of sequence A is 220. What is the sum of a different sequence of five consecutive numbers whose second lowest number in 37 less than double of the lowest number of sequence A?

(A) 220
(B) 221
(C) 223
(D) 225
(E) 235

Correct Answer: (A)
Solution with Explanation:

Approach Solution : 1

Sequence A would consist of the numbers X-4, X-2, X, X+2, X+4, where x is the median and average of the five numbers and their sum is 220.
Therefore X = 44
The second lowest in the series of 5 numbers which are y-2, y-1, y, y+1, y+2 =>
Y-1 = 2(x-4)-37 = 43.
y=x and median in an arithmetic sequence of the same number of elements.
Therefore the sum of a different sequence of five numbers can be calculated as 42 + 43 + 44 + 45 + 46 = 220.

Approach Solution : 2

Median A = Mean A = 44.
The lowest in A is 40
Doubling the lowest in A will result in 80.
The Second-lowest in B can be calculated as 80-37 = 43
The other series B is 42, 43, 44, 45, 46.
Last digit is a 0.
Therefore 220 is the answer from the given options.

Approach Solution : 3

It is given that x + x + 2 + x + 4 + x + 6 + x +8 = 220
Now, we can write that 5x + 20 = 220 => x = 40
The Second lowest number of different set = (2*40) - 37 = 43
Therefore the Required sum =42 + 43 + 44 + 45 + 46 = 220

“The Sum Of Five Consecutive Even Numbers Of Sequence A Is 220” - is a subject that the GMAT quantitative reasoning section covers. A school needs to be proficient in a variety of qualitative skills to answer the GMAT Problem Solving questions correctly. There are 31 questions in the GMAT Quant section as a whole. The GMAT Quant topics' problem-solving section calls for the resolution of calculative mathematical puzzles.

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