
Question: Starting from the same point, a sparrow and a hawk flew in opposite directions. Each traveled at a constant speed until they were 200 feet apart. How far did the sparrow travel?
“Starting from the same point, a sparrow and a hawk flew in opposite directions. Each traveled at a constant speed until they were 200 feet apart. How far did the sparrow travel?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "GMAT Quantitative Review". GMAT Quant section consists of a total of 31 questions. GMAT Data Sufficiency questions consist of a problem statement followed by two factual statements. GMAT data sufficiency comprises 15 questions which are two-fifths of the total 31 GMAT quant questions.
Answer:
Approach Solution 1:
(1) \(\frac{s}{h}=\frac{3}{2}\) where s is speed of sparrow and h is speed of hawk
h = \(s\frac{2}{3}\) , as sparrow and hawk flew for same time and the speed of hawk was \(\frac{2}{3}\) of sparrow’s, hence hawk would cover \(\frac{2}{3}\) of the distance as would cover sparrow --- \(Ds+\frac{2}{3}Ds=200\), where Ds = 120
Hence sufficient.
(2) s = h – 5, clearly insufficient to calculate Ds.
Correct option: A
Approach Solution (2):
Time for which sparrow and hawk will fly will be equal, let’s say T
Stmnt1: Ratio of speed is 3:2 (sparrow : hawk)
Let speed be 2S for hawk and sparrow be 3S
Now we have total distance = 200 = 3S*T + 2S*T = 5ST
and T = \(\frac{200}{5S}=\frac{40}{S}\)
Distance traveled by Sparrow is 3S* \(\frac{40}{S}\) = 120 feet.
Hence suff
Stmnt 2: let speed of hawk be S and speed of sparrow is S+ 5
Time will remain same
so we get 200 = S* T + (S+5)*T = (2S + 5)T
=> T = 200/(2S + 5)
Speed of sparrow = (S+5) * 200/(2S + 5)
This can give us more than 1 value
e.g S = 5/7.5/10
So insuff
Correct option: A
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