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An Industrial Loom Weaves 0.128 metres of Cloth Every Second GMAT Problem Solving

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Sayantani Barman

Experta en el extranjero | Updated On - Feb 9, 2023

Question: An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?

(A) 178
(B) 195
(C) 204
(D) 488
(E) 492

Correct Answer: E
Solution and Explanation:
Approach Solution 1:

For this GMAT problem-solving question, you can only use the data given to you. This group contains problems from several branches of mathematics. This one in particular can be traced back to circles.
The way the options are laid up makes picking the best one difficult. Candidates must comprehend the best tactic to get the desired result. Only one of the five choices offered is correct.

Given in the question that every second, an industrial loom makes 0.128 meters of cloth. It has asked how long, in seconds, will it take the loom to weave 25 meters of fabric.

Here, the weaving rate is given to be 0.128 meters of cloth /s.
We must determine the time needed for 25 meters.

Therefore, the time needed is 25 / 0.128.
= 25*100/12.8

Knowing that 25/12.5 Equals 2
Thus, 25/12.8 will be only a little bit less than 2.
Then the final answer will be slightly less than 200.

B is the correct answer.

Approach Solution 2:

For this GMAT problem-solving question, you can only use the data given to you. This group contains problems from several branches of mathematics. This one in particular can be traced back to circles.
The way the options are laid up makes picking the best one difficult. Candidates must comprehend the best tactic to get the desired result. Only one of the five choices offered is correct.

As stated in the question, every second, an industrial loom makes 0.128 meters of cloth. It has been asked how long, in seconds, it will take the loom to weave 25 meters of fabric.

Here, the weaving rate is given to be 0.128 meters of cloth /s.
We must determine the time needed for 25 meters.

Therefore, the time needed is 25 / 0.128.
= 25*100/12.8

Now the value of this is 195.xx
Here, xx could be any decimal value.

The only value close to this is 195.

It should be kept in mind that the candidate can calculate the exact value of the fraction but it will consume much time of the exam. Using approximation techniques or shortcuts is preferred to be used during the exam. Hence these examples are given to provide an idea about the process of solving this kind of problem.
Hence, B is the correct choice.

Approach Solution 3:

For this GMAT problem-solving question, you can only use the data given to you. This group contains problems from several branches of mathematics. This one in particular can be traced back to circles.

The way the options are laid up makes picking the best one difficult. Candidates must comprehend the best tactic to get the desired result. Only one of the five choices offered is correct.

As stated in the question, every second, an industrial loom makes 0.128 meters of cloth. It has been asked how long, in seconds, it will take the loom to weave 25 meters of fabric.

Let the required time be x seconds.
More metres, more time it will take.
0.128: 25 :: 1:x
We get 0.128x = 25
X = 25 / 0.128 = 25 * 1000/128
x=195.31

B is the only close option.

“An industrial loom weaves 0.128 metres of cloth every second. Approxim" - is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been borrowed from the book “GMAT Official Guide Quantitative Review”.

To understand GMAT Problem Solving questions, applicants must possess fundamental qualitative skills. Quant tests a candidate's aptitude in reasoning and mathematics. The GMAT Quantitative test's problem-solving phase consists of a question and a list of possible responses. By using mathematics to answer the question, the candidate must select the appropriate response. The problem-solving section of the GMAT Quant topic is made up of very complicated math problems that must be solved by using the right math facts.

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*The article might have information for the previous academic years, please refer the official website of the exam.

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