JEE Main Study Notes for Nature of Roots of Quadratic Equations: The nature of roots of a quadratic equation ax2+bx+c=0 is determined by the discriminant, D =b2-4ac. If D=0, the equation has two real roots. If D<0, the equation has two complex roots. If D>0, the equation has two real and distinct roots.
Quick Links:
JEE Main 2022 Application Process | JEE Main 2022 Exam Dates | JEE Main Mathematics Question Paper | JEE Main 2022 Preparation |
Must Read:
The roots of the equation are the values of the variable x that fulfill the equation in one variable. These roots could be simple or complicated. A quadratic polynomial becomes a quadratic equation when it is equal to zero. The roots of the quadratic equation are the values of x that satisfy the equation.
The discriminant is a component of the quadratic formula, which is found below the square root. The discriminant of a quadratic equation is significant because it indicates the number and kind of solutions. This knowledge is useful since it acts as a double check when utilizing any of the four ways to solve quadratic equations (factoring, completing the square, using square roots, and using the quadratic formula).
The discriminant of a quadratic equation is calculated using the coefficients of the equation ax^2+bx+c =0 and is represented by the number D= b^2-4ac. The discriminant reveals the nature of an equation's roots.
The quadratic formula is used to find b^2 – 4ac.
The table below covers the many types of roots that are related to the determinant's values.
Discriminant | Roots |
---|---|
D < 0 | Two roots that are complex conjugates |
D = 0 | One real root of multiplicity two |
D > 0 | Two distinct real roots |
D = positive perfect square | Two distinct rational roots (with the assumption that a, b, and c are rational) |
Check JEE Main Study Notes for Probability
For example, look at the quadratic equation y = 3x^2+9x+5. Find its discriminant.
Solution: The quadratic equation given is y = 5x^2-4x-3.
Discriminant formula is D = b^2-4ac.
This means, a= 5, b= 4 and c= 3
Therefore, the discriminant is,
D= 16-4.5.-3
=16+60
=76
Also Check
The nature of the roots of the quadratic equation is determined by the discriminant's value, D=b^2–4ac.Depending upon D, then the quadratic equation's roots can be real or imaginary, depending on the criteria:
When b^2–4ac>=0, the roots are real, and when b^2–4ac < 0, the roots are fictional. Real roots are divided into two categories: rational roots and illogical roots.
The roots of a quadratic equation are rational if ax^2+bx+c=0, where a,b,c are rational numbers, and b^2–4ac>0, i.e., D>0 and a perfect square.
The roots are irrational if a quadratic equation is provided by ax^2+bx+c=0, where a,b,c are rational values and b^2–4ac>0, i.e., D>0 and not a perfect square. Using the discriminant approach, we may categorize the roots of quadratic equations into three kinds.
There will be two roots in the quadratic equation ax^2+bx+c=0, which can be equal or unequal, real or unreal, or imaginary.
If D=b^2–4ac>0, we can get two separate real roots.
This can be depicted graphically as seen below. The graph of the quadratic equation intersects the x-axis at two unique locations, as seen in the graphical representation. The zeros or roots are these two separate points.
Example:
Take the quadratic equation x^2–7x+12=0
Here, a=1, b=7, and c=12 are the values.
D=b^2–4ac=(–7)2–4(1)(12)=1 discriminant
x^2–7x+12=0 has two unique real roots since the discriminant is bigger than zero.
The quadratic formula can be used to find the roots.
x=–(–7)±12×1=7±12
=7+12,7–12
=82,62
=4,3
Check:
If D=b^2–4ac=0, we have two equal real roots in a quadratic equation ax^2+bx+c=0. The graph of the quadratic equation with equal roots only touches the x-axis at one point in the graphical depiction. The value of x is taken from this point. However, we can say that x has two equal solutions.
Example:
Consider the expression x^2–2x+1=0. D=b^2–4ac=(–2)2–4x1x1=0 is a discriminant.
x^2–2x+1=0 has two equal roots because the discriminant is 0.
To find the roots, the quadratic formula is used.
x= -(-2) +-0/2x1= 2/2=1
There will be no real roots in the quadratic equation ax^2+bx+c=0 if D=b^2–4ac0. Complex roots or imagined roots are the names given to the roots. 3x^2+x+4=0, for example, has two complicated roots: b^2–4ac=(1)2–434=–47, which is less than zero.
Also, Check
Given below are the previous year’s questions that came in JEE Main with solutions. Each question carries 4 marks.
Question 1: If equations x2+2x+3=0 and ax2+bc+c=0,a,b,c ∈ R, have a common root , then a:b:c is: (1) 1:2:3 (2) 3:2:1 (3) 1:3:2 (4) 3:2:1 [JEE-MAIN-2013]
Answer: (1)x2+2x+3=0D<0
Therefore, ax2+bc+c=0has both common roots
Hence, a:b:c=1:2:3
Question 2: Let ???? and ???? be the roots of equation x2-6x-2=0. If aₙ=????n- ????n , for n≥1, then value of (a₁₀-2a₈)/2a₉ is equal to : (1) 3 (2) -3 (3) 6 (4) -6 [JEE-MAIN-2015]
Answer: (1)Given x2-6x-2=0
Therefore, aₙ₊₂-6aₙ₊₁-2aₙ=0
(aₙ₊₂-2aₙ)/2aₙ₊₁=3
Now, put n=8
(a₁₀-2a₈)/2a₉= 3
Question 3: The sum of all real values of x satisfying the equation (x2-5x+5)x2+4x-60=1is : (1) 5 (2) 3 (3) -4 (4) 6 [JEE-MAIN-2016]
Answer: (2) x2-5x+5=1⇒x=1,4
x2-5x+5=-1⇒x=2,3but 3 is rejected x2+4x-60=0⇒x=-10,6
Sum = 3
Question 4: If ????, ????∈C are the distinct roots of the equation x2-x+1=0 , then ????¹⁰¹+ ????¹⁰⁷ is equal to - [JEE-MAIN-2018]
Answer: ????, ???? are roots of the x2-x+1=0
Therefore, ????= -⍵ and ???? = -⍵²
Where ⍵ is non-real cube root of unity
So, ????¹⁰¹+ ????¹⁰⁷
⇒(-⍵)¹⁰¹ +(-⍵²)¹⁰⁷
⇒ -[⍵²+⍵]
⇒ -[-1]=1
(As 1+⍵+⍵²=0 & ⍵³=1)
Question 5: If the cube roots of unity are 1, ω, ω2, then find the roots of the equation (x − 1)3 + 8 = 0. [JEE-MAIN- 2019 April]
Answer
(x − 1)3 = −8 ⇒ x − 1 = (−8)1/3
x − 1 = −2, −2ω, −2ω2
x = −1, 1 − 2ω, 1 − 2ω2
Question 6: Let α and β be the roots of equation px^2 + qx +r= 0, p ≠ 0. If p, q, r are in A.P. and 1⁄????+1⁄????= 4 then the value of |α -β| is: [JEE-MAIN- 2014]
Answer.
Let p, q, r are in AP ⇒ 2q = p + r ...(i)
Given 1⁄????+1⁄????= 4 ⇒
We have a + b = – q/p and ab =
4 ⇒ q = -4r ....(ii)
From (i), we have 2( – 4r) = p + r
⇒ p = –9r
q = – 4r
Now
Question 7: If x = a + b, y = aα + bβ and z = aβ + bα, where α and β are complex cube roots of unity, then what is the value of xyz? [JEE-MAIN-2017]
Answer
If x = a + b, y = aα + bβ and z = aβ + bα, then xyz = (a + b) (aω + bω2) (aω2 + bω),where α = ω and β = ω2 = (a + b) (a2 + abω2 + abω + b2)
= (a + b) (a2− ab + b2)
= a3 + b3
Mathematics has equal weightage to Physics and Chemistry in JEE, however, Mathematics has an advantage over the other two because if two or more candidates have the same overall score, the score in mathematics is used as a tie-breaker. JEE Main 2022 Math Syllabus contains a balance of difficult and easy topics. Given below are the tips to score well in Mathematics:
Related Link: JEE Main Important Books
Related Links :
Nature of roots which is a sub-topic of quadratic equations can take up to 2-3 weeks to finish. Depending upon the calculation speed of the candidate, the topic can be moderate to slightly difficult. A table is provided below to provide an idea for the candidates.
Difficulty Level | Slightly Difficult |
---|---|
Weightage in JEE Mains Examination | 3.33% |
Years Featuring Most Questions from the Topic |
|
Time Needed for Preparation: Optimistic Scenario | 1-2 Weeks (if basics are clear) |
Time Needed for Preparation: Pessimistic Scenario | 3-5 Weeks or more (if basic needs to be revised) |
Question: Which is the hardest topic in JEE Main 2022 math syllabus?
Answer: The hardest Topic in JEE Main 2022 Math syllabus are Complex Numbers, Probability and Statistics, Algebra, Trigonometry, Calculus, and Coordinate Geometry.
Question: How many questions are there in JEE Main 2022 Maths section?
Answer: JEE Main question paper is divided into three sections- Physics, Chemistry, and Mathematics. Each section consists of 25 questions. So, JEE Main Maths Section has 25 Questions.
Question: What will be the total weightage of Quadratic equations in JEE Main 2022 Exam?
Answer: As per previous year’s paper analysis, the number of questions asked from quadratic equations in JEE Mains, on average across previous years is, 2. Each question carries 4 marks. The total weightage of Quadratic Equation in the JEE Main paper can be expected to be around 8 marks.
Question: What is the negative marking in JEE Main 2022?
Answer: For every incorrect answer, no negative marking is there for questions with numerical values. Without that, one mark will be deducted for every wrong answer.
Question: What will be the mode of JEE Main 2022 examination?
Answer: The mode of JEE main 2022 examination is online. Only Part 3, paper with drawing tests will be carried offline- pen and paper mode.
Question: What is the general equation of the Quadratic Equation, a part of JEE Main 2022 Mathematics Syllabus?
Answer: The general equation is : ax^2+bx+c=0. Its roots are provided by x=–b±b^2–4ac√2a. Determinant (D) is provided by: D=b^2–4ac.
Quick Links`:
*The article might have information for the previous academic years, please refer the official website of the exam.