JNEC Aurangabad offers B.Tech Computer Science and Engineering as a 4 Year Full Time program. For admission into JNEC Aurangabad B.Tech Computer Science and Engineering, a candidate must clear 10+2. JNEC Aurangabad offers a total of 180 seats for B.Tech Computer Science and Engineering.
JNEC Aurangabad total tutuion fees for B.Tech Computer Science and Engineering in 2025 is ₹ 6 Lakhs for the complete course duration. B.Tech Computer Science and Engineering total fee at JNEC Aurangabad is ₹ 6.46 Lakhs in 2025. However, the total fee was ₹ 6.37 Lakhs in 2022.
Course Duration
4 YearsTuition Fees
1.5 Lakhs1 Year Fees
1.69 LakhsTotal Fees
6.46 Lakhs| Year | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| Total Year Wise fees | ₹1.69 Lakhs | ₹1.59 Lakhs | ₹1.59 Lakhs | ₹1.59 Lakhs |
| Total Fees | ₹169000 | ₹159000 | ₹159000 | ₹159000 |
| Tuition fees | ₹150000 | ₹150000 | ₹150000 | ₹150000 |
| Exam fees | ₹5000 | ₹5000 | ₹5000 | ₹5000 |
| Caution fee* | ₹5000 | - | - | - |
| miscellaneous fees | ₹9000 | ₹4000 | ₹4000 | ₹4000 |
| Year | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| Total Year Wise fees | ₹1.69 Lakhs | ₹1.56 Lakhs | ₹1.56 Lakhs | ₹1.56 Lakhs |
| Total Fees | ₹169000 | ₹156000 | ₹156000 | ₹156000 |
| Tuition fees | ₹150000 | ₹150000 | ₹150000 | ₹150000 |
| other fee | ₹19000 | ₹6000 | ₹6000 | ₹6000 |
1. Maharashtra State Candidate.
(i) The Candidate should be an Indian National and having domicile of Maharashtra state and/or born in Maharashtra state.
(ii) Passed HSC or its equivalent examination with Physics and Mathematics as compulsory subjects along with one of the Chemistry or Biotechnology or Biology or Technical Vocational subject or Computer Science or Information Technology or Informatics Practices or Agriculture or Engineering Graphics or Business Studies, and obtained at least 45% marks (at least 40% marks, in case of Backward class categories and Persons with Disability candidates belonging to Maharashtra State only) in the above subjects taken together and the candidate should have appeared in MGMU-CET 2023/ MHT-CET 2023/ PERA CET 2023/ JEE (Main) Paper-I 2023 and should obtain non zero score in MGMU-CET 2023/ MHT-CET 2023/ PERA CET 2023/ JEE (Main) Paper-I 2023. However, preference shall be given to the candidate obtaining non-zero positive score in MGMU-CET 2023 over the candidates who obtained non-zero score in MHT-CET 2023/ PERA CET 2023.
(ii)Passed Diploma in Engineering and Technology and obtained at least 45% marks (at least 40% marks, in case of Backward class categories and Persons with Disability candidates belonging to Maharashtra State only).
2. All India Candidates –
(i) The Candidate should be an Indian National.
(ii) Passed HSC or its equivalent examination with Physics and Mathematics as compulsory subjects along with one of the Chemistry or Biotechnology or Biology or Technical Vocational subject or Computer Science or Information Technology or Informatics Practices or Agriculture or Engineering Graphics or Business Studies , and obtained at least 45% marks (at least 40% marks, in case of Backward class categories and Persons with Disability candidates belonging to Maharashtra State only) in the above subjects taken together and candidate should have appeared in MGMU-CET 2023/ MHT-CET 2023/ PERA CET 2023/ JEE (Main) Paper-I 2023 and should obtain non-zero score in MGMU-CET 2023/ MHT-CET 2023/ PERA CET 2023/ JEE (Main) Paper-I 2023. However, preference shall be given to the candidate obtaining non-zero positive score in JEE Mains Paper-I over the candidates who obtained non-zero score in MGMU-CET 2023/ MHT-CET 2023/ PERA CET 2023.
(ii) Passed Diploma in Engineering and Technology and obtained at least 45% marks (at least 40% marks, in case of Backward class categories and Persons with Disability candidates belonging to Maharashtra State only)
| Highest Placement | ₹ 7.5 Lakhs |
| Average Placement | ₹ 3.5 Lakhs |
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