JNTUK offers B.Tech Computer Science and Engineering as a 4 Year Full Time program. For admission into JNTUK B.Tech Computer Science and Engineering, a candidate must clear 10+2 with 45% + AP EAMCET. JNTUK offers a total of 240 seats for B.Tech Computer Science and Engineering.
JNTUK total tutuion fees for B.Tech Computer Science and Engineering in 2018 is ₹ 3.04 Lakhs for the complete course duration. B.Tech Computer Science and Engineering total fee at JNTUK is ₹ 3.04 Lakhs in 2018.
Course Duration
4 YearsTuition Fees
76 K1 Year Fees
76 KTotal Fees
3.04 Lakhs| Year | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| Total Year Wise fees | ₹76,000 | ₹76,000 | ₹76,000 | ₹76,000 |
| Total Fees | ₹76000 | ₹76000 | ₹76000 | ₹76000 |
| Tuition fees | ₹76000 | ₹76000 | ₹76000 | ₹76000 |
Candidate must have pass 10+2 in science stream with 50% or 45% for SC/ST from recognised board.
Candidate must have to clear EAMCET entrance exam.
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