RRCE offers BE Computer Science And Engineering as a 4 Year Full Time program. For admission into RRCE BE Computer Science And Engineering, a candidate must clear 10+2 with 45% + KCET. RRCE offers a total of 180 seats for BE Computer Science And Engineering.
BE Computer Science And Engineering total fee at RRCE is ₹ 10.66 Lakhs in 2024. However, the total fee was ₹ 7.76 Lakhs in 2023.Course Duration
4 YearsTotal Fees
10.66 Lakhs| Total Fees | ₹10.66 Lakhs |
| Total Fees | ₹10.66 Lakhs |
The applications for admissions to RRCE have to be submitted online through the official portal of the college. Here are the steps to apply:
Aspirants seeking admission to 4 year Full-time B.E Program should meet the following criteria as specified by the institute.
Academic Requirement:
Candidate should pass in PUC or 10+2 equivalent examination with minimum of 45% (40% for SC / ST and OBC groups) marks aggregate in Physics, Mathematics and any one of the following subjects – Biology / Chemistry / Computer Sciences / Electronics.
Entrance Exam:
Candidates must qualify KCET Entrance exam.
RajaRajeshwari College of Engineering offers four-year BE in 6 specializations i.e. Civil Engineering, Computer Science and Engineering, Electrical, and Electronics Engineering, Electronics and Communication Engineering, Information Science and Engineering, Mechanical Engineering.
| Duration | 4 years |
| Type | Full-Time |
| No of specializations | 6 |
| Basic eligibility criteria | Pass in 10+2 with 45% marks in PCM |
| Basic selection criteria | JEE Mains/KCET Score |
To be eligible for the admission process of RajaRajeswari College of Engineering B.E admissions must have passed the 10+2 intermediate examinations from a recognized board with Physics, Chemistry, Maths as compulsory subjects.
A rank is a must in Entrance Examinations like CET, KRLM, COMED–K, AIET, AIEEE etc. After the merit list is declared it is followed by online counseling conducted by Visvesvaraya Technological university (VTU) for the seat allotment
For cut-off of the exams Check here.
Fee for CET students = 98,984/-
Fee for COMEDK Students = 2,42,156/-
And other fee = 19,700/-
| Highest Placement | ₹ 8.3 Lakhs |
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