What is the cutoff for VIIT Pune CSE/IT?
Posted On - Dec 4, 2020VIIT Pune cutoff for CSE/IT usually stays around 100 or above in CET examination. During 2021 admission the required CET cutoff was 90.53 and 92.47 for IT and CSE, respectively. For TFWS seats, the required score usually stays above 125 or more.
VIIT Pune accepts JEE Main scores as well. CSE and IT cutoff scores for JEE Mains 2021 were 2401 and 3012, respectively.
VIIT Pune accepts JEE Main score and CET scores for its admission process of Bachelors of Engineering (B.E). For the Computer Science branch, the cut-off in JEE Main was around 38k rank and for Information Technology it was around 48k rank.
Cutoff - JEE Main:
In 2019 the JEE Mains cutoff for CSE was as follows.
|
Category |
Cutoff by Rank |
|
BE in Computer Science |
38078 |
|
BE in Information Technology |
48292 |
For CET the cut-off is 100 +/- 5 to 10 marks to get CS/IT in VIIT Pune. You need to have a rank of 100 or above in order to seek admission for CS/IT at VIIT Pune. If you want to apply through TFWS (Tuition Fee Waiver Scheme) seats, you need a score of 125 or above in CET for IT/CS.
