Question

The height from Earth's surface at which acceleration due to gravity becomes \(\frac{g}{4}\) is \(\_\_\)? (Where \(g\) is the acceleration due to gravity on the surface of the Earth and \(R\) is the radius of the Earth.)

• A. \(\sqrt{2}R\).
• B. \(R\).
• C. \(\frac{R}{\sqrt{2}}\).
• D. \(2R\).

Hint:

The acceleration due to gravity decreases with the square of the distance from the center of the Earth. Use \(g_h = g \left( \frac{R}{R + h} \right)^2\) for calculations involving heights above the Earth's surface.