Question:medium

"The height from Earth's surface at which acceleration due to gravity becomes \( g/4 \), where \( g \) is acceleration due to gravity on the surface of Earth and \( R \) is the radius of Earth?"

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The acceleration due to gravity decreases with height and follows the relation \( g_h = g (R / (R + h))^2 \).
Updated On: Nov 26, 2025
  • \( \sqrt{2}R \).
  • \( R \).
  • \( R/\sqrt{2} \).
  • \( 2R \).