Question:medium

At a height \( h \) above the Earth's surface, the acceleration due to gravity becomes \( \frac{g}{\sqrt{3}} \). What is the value of \( h \) in terms of the Earth's radius \( R \)?

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When working with gravitational problems involving height above the Earth's surface, remember to use the formula for gravity variation with height: \( g_h = \frac{g}{(1 + \frac{h}{R})^2} \).
Updated On: Nov 26, 2025
  • \( R \)
  • \( \sqrt{2}R \)
  • \( 2R \)
  • \( \frac{R}{2} \)