Question:medium

The escape velocity from the surface of a planet is \(v_e\). What will be the escape velocity from a planet whose mass and radius are twice that of the original planet?

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Escape velocity is proportional to \( \sqrt{\frac{M}{R}} \). If both mass and radius double, the ratio remains unchanged.
Updated On: Nov 26, 2025
  • \(v_e\)
  • \(2v_e\)
  • \(\sqrt{2}v_e\)
  • \(4v_e\)