Question

If you are provided a set of resistances $2 \, \Omega$, $4 \, \Omega$, $6 \, \Omega$, and $8 \, \Omega$. Connect these resistances so as to obtain an equivalent resistance of \(\frac{46}{3}  \Omega.\)

• A. $4 \, \Omega$ and $6 \, \Omega$ are in parallel with $2 \, \Omega$ and $8 \, \Omega$ in series
• B. $6 \, \Omega$ and $8 \, \Omega$ are in parallel with $2 \, \Omega$ and $4 \, \Omega$ in series
• C. $2 \, \Omega$ and $6 \, \Omega$ are in parallel with $4 \, \Omega$ and $8 \, \Omega$ in series
• D. $2 \, \Omega$ and $4 \, \Omega$ are in parallel with $6 \, \Omega$ and $8 \, \Omega$ in series

Hint:

When combining resistances, remember that:
The equivalent resistance of resistors in series is the sum of their resistances.
The equivalent resistance of resistors in parallel is given by the reciprocal of the sum of the reciprocals of their resistances.