Question

Light of wavelength \( 400\, \text{nm} \) falls on a metal with work function \( \phi = 2.0\, \text{eV} \). If the intensity of the light is doubled, what happens to the maximum kinetic energy of the emitted photoelectrons?

• A. It doubles
• B. It becomes zero
• C. It increases by a factor of \( \sqrt{2} \)
• D. It remains the same

Hint:

\textbf{Tip:} In photoelectric effect, intensity affects the number of emitted electrons, but not their maximum kinetic energy.