Oxidation number of H in NaH, CaH$_2$, and LiH, respectively is:
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In metal hydrides (e.g., NaH, CaH$_2$, LiH), hydrogen acts as a hydride ion (\( H^- \)) with an oxidation number of \(-1\). This is different from most other compounds, where hydrogen typically has an oxidation number of \(+1\).