A bob of mass \( m \) is suspended by a light string of length \( L \). It is imparted a minimum horizontal velocity at the lowest point A such that it just completes half a circle, reaching the topmost position B. The ratio of kinetic energies \(\left(\frac{K.E.}{K.E.}\right)_A \), \(\text{to}\), \(\left(\frac{K.E.}{K.E.}\right)_B\)is:
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In vertical circular motion, use \textbf{energy conservation} to relate velocities at different points. At the topmost point, potential energy is maximum, and kinetic energy is minimum.