A simple pendulum has a time period of 2 s on Earth's surface. What is its time period at a height equal to the Earth's radius (R)? (Acceleration due to gravity at height h is \( g_h = \frac{g}{(1 + h/R)^2} \)).
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Account for variation in gravity with height using \( g_h = \frac{g}{(1 + h/R)^2} \).