Question

What will be the acceleration due to gravity at a depth \( d \), where \( g \) is the acceleration due to gravity on the surface of the Earth?

• A. \(\frac{g}{\left(1 + \frac{d}{R}\right)^2}\)
• B. \( g \left[ 1 - \frac{2d}{R} \right] \)
• C. \(\frac{g}{\left(1 - \frac{d}{R}\right)^2}\)
• D. \( g \left[ 1 - \frac{d}{R} \right] \)

Hint:

Acceleration Due to Gravity:

• At a height h above the Earth's surface: g' = g × (R / (R + h))²
• At a depth d below the Earth's surface: g' = g × (1 - d / R)
• Note: Gravity decreases linearly with depth inside the Earth.