Question:medium

The range of a projectile projected at an angle of \( 15^\circ \) with the horizontal is \( 50 \) m. If the projectile is projected with the same velocity at an angle of \( 45^\circ \), then its range will be:

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For a given velocity, the maximum range occurs at \( 45^\circ \). The range is proportional to \( \sin(2\theta) \), which helps in comparative range calculations.
Updated On: Nov 26, 2025
  • \( 50 \) m
  • \( 50\sqrt{2} \) m
  • \( 100 \) m
  • \( 100\sqrt{2} \) m