Question:medium

What volume of \( 0.5 \, \text{M} \, \text{NaOH} \) is required to neutralize \( 50 \, \text{mL} \) of \( 1 \, \text{M} \, \text{HCl} \)?

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For neutralization, use the formula \( C_1 V_1 = C_2 V_2 \), where \( C_1 \) and \( V_1 \) are the concentration and volume of the acid, and \( C_2 \) and \( V_2 \) are the concentration and volume of the base.
Updated On: Nov 26, 2025
  • \( 50 \, \text{mL} \)
  • \( 100 \, \text{mL} \)
  • \( 200 \, \text{mL} \)
  • \( 25 \, \text{mL} \)