Question:medium

The refractive index \( \mu \) of the material of a prism is given by: % Formula for Refractive Index \[ \mu = \frac{\sin \left( \frac{A + \delta_m}{2} \right)}{\sin \left( \frac{A}{2} \right)} \] where \( A \) is the apex angle of the prism and \( \delta_m \) is the angle of minimum deviation.

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The refractive index of a prism is given by:
\( \mu = \frac{\sin \left( \frac{A + \delta_m}{2} \right)}{\sin \left( \frac{A}{2} \right)} \)
The minimum deviation angle \( \delta_m \) is found using \( \delta_m = 180^{\circ} - 2A \).
Updated On: Nov 26, 2025
  • \( \delta_m = 180^{\circ} - 4A \)
  • \( \delta_m = 180^{\circ} - 3A \)
  • \( \delta_m = 180^{\circ} - 2A \)
  • \( \delta_m = 180^{\circ} - A \)