Question:medium

If \( f(x) = \cos^{-1 } \left( \frac{\sqrt{2x^2 + 1}}{x^2 + 1} \right) \), then the range of \( f(x) \) is:

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For inverse trigonometric functions like \( \cos^{-1} \), the range is typically \( [0, \pi] \), but the values inside the function must stay within the domain of -1 to 1.

Updated On: Nov 26, 2025
  • \( [0, \pi] \)
  • \( \left[ 0, \frac{\pi}{4} \right] \)
  • \( \left[ 0, \frac{\pi}{3} \right] \)
  • \( \left[ 0, \frac{\pi}{2} \right] \)