Question:medium

If \( \cot(\cos^{-1} x) = \sec \left( \tan^{-1} \left( \frac{a}{\sqrt{b^2 - a^2}} \right) \right) \), then:

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For inverse trigonometric functions, rewrite in terms of known trigonometric identities to simplify expressions.
Updated On: Nov 26, 2025
  • \( \frac{b}{\sqrt{2b^2 - a^2}} \)
  • \( \frac{\sqrt{b^2 - a^2}}{ab} \)
  • \( \frac{a}{\sqrt{2b^2 - a^2}} \)
  • \( \frac{\sqrt{b^2 - a^2}}{a} \)