Question:medium

If \[ y = \tan^{-1} \left( \frac{1}{x^2 + x + 1} \right) + \tan^{-1} \left( \frac{1}{x^2 + 3x + 3} \right) + \tan^{-1} \left( \frac{1}{x^2 + 5x + 7} \right) + \cdots { (to n terms)} \], then \(\frac{dy}{dx}\) is:

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For trigonometric series involving inverse functions and variables, look for telescoping patterns to simplify the expression before differentiating.
Updated On: Nov 26, 2025
  • \( \frac{1}{x^2 + n^2} - \frac{1}{x^2 + 1} \)
  • \( \frac{1}{(x + n)^2 + 1} - \frac{1}{x^2 + 1} \)
  • \( \frac{1}{x^2 + (n + 1)^2} - \frac{1}{x^2 + 1} \)
  • None of these