Question:medium

Evaluate the integral: $\int_{-\pi}^{\pi} x^2 \sin(x) \, dx$

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The integral of an odd function over a symmetric interval is always 0.
Updated On: Nov 26, 2025
  • \( \pi^2 \)
  • \( \frac{\pi^2}{2} \)
  • 0
  • \( 2\pi^2 \)