An alternating voltage \( V(t) = 220 \sin 100\pi t \) volt is applied to a purely resistive load of \( 50\Omega \). The time taken for the current to rise from half of the peak value to the peak value is:
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The time taken for voltage in an AC waveform to rise from half to peak is always \( \frac{T}{6} \), where \( T \) is the time period.