Question:medium

A heavy box of mass 50 kg is moving on a horizontal surface. If the coefficient of kinetic friction between the box and the horizontal surface is 0.3, then the force of kinetic friction is:

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The force of kinetic friction is given by \( F_k = \mu_k \cdot N \), where \( N \) is the normal force and \( \mu_k \) is the coefficient of kinetic friction.
Updated On: Nov 26, 2025
  • 14.7 N
  • 147 N
  • 1.47 N
  • 1470 N