Question

Two straight conducting plates form an angle θ where their ends are joined. A conducting bar in contact with the plates and forming an isosceles triangle with them, starts at the vertex at time t = 0 and moves with constant velocity v to the right as shown in the figure. A magnetic field B points out of the page. The magnitude of emf induced at t = 1 second will be:

• A. \( Bv \tan \frac{\theta}{2} \)
• B. \( 2Bv^2 \tan \frac{\theta}{2} \)
• C. \( 2Bv^2 \cot \frac{\theta}{2} \)
• D. \( 2Bv^2 \sin \frac{\theta}{2} \)

Hint:

The induced emf in a moving conductor depends on the velocity of the conductor and the angle between the conducting plates, as wellas the magnetic field strength.