Question

Two identical point masses P and Q, suspended from two separate massless springs of spring constants \(k_1\) and \(k_2\), respectively, oscillate vertically. If their maximum velocities are the same, the ratio of the amplitude of P to the amplitude of Q is :

• A. \( \sqrt{\frac{k_2}{k_1}} \)
• B. \( \sqrt{\frac{k_1}{k_2}} \)
• C. \( \frac{k_2}{k_1} \)
• D. \( \frac{k_1}{k_2} \)

Hint:

The maximum velocity in SHM is \( v_{max} = A \omega = A \sqrt{k/m} \). Equate the maximum velocities for the two masses and solve for the ratio of their amplitudes.