Question

The work function of a metal is 2 eV. What is the threshold frequency for the photoelectric emission? (Take Planck's constant $ h = 6.63 \times 10^{-34} \, \text{Js} $, $ 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} $)

• A. \(4.8 \times 10^{14} \, \text{Hz}\)
• B. \(5.2 \times 10^{14} \, \text{Hz}\)
• C. \(6.2 \times 10^{14} \, \text{Hz}\)
• D. \(7.4 \times 10^{14} \, \text{Hz}\)

Hint:

To find the threshold frequency, always convert the work function from eV to joules before using \( f = \frac{E}{h} \).