Question

The variation of displacement with time of a simple harmonic motion (SHM) for a particle of mass \( m \) is represented by: \[ y = 2 \sin \left( \frac{\pi}{2} + \phi \right) \, \text{cm} \] The maximum acceleration of the particle is:

• A. \( \frac{\pi^2}{2} \, \text{cm/sec}^2 \)
• B. \( \frac{\pi}{2m} \, \text{cm/sec}^2 \)
• C. \( \frac{\pi^2}{2m} \, \text{cm/sec}^2 \)
• D. \( \frac{\pi^2}{2} \, \text{cm/sec}^2 \)

Hint:

In SHM, the maximum acceleration is given by \( a_{\text{max}} = \omega^2 A \), where \( \omega \) is the angular frequency and \( A \) is the amplitude.