Question:medium
The value of \( \displaystyle \int_0^{1.5} \left\lfloor x^2 \right\rfloor \, dx \) is:
The value of \( \displaystyle \int_0^{1.5} \left\lfloor x^2 \right\rfloor \, dx \) is:
Show Hint
When integrating a floor function, split the integral at points where the floor value changes (discontinuities), and compute each interval separately.
Updated On: Nov 28, 2025
- \( 2 \)
- \( 2 - \sqrt{2} \)
- \( 2 + \sqrt{2} \)
- \( \sqrt{2} \)