Question

The straight wire AB carries a current \(I\). The ends of the wire subtend angles \(\theta_1\) and \(\theta_2\) at the point \(P\) as shown in the figure. The magnetic field at the point \(P\) is: 
 

 

• A. \(\frac{\mu_0 I}{4\pi d} (\sin \theta_1 - \sin \theta_2)\)
• B. \(\frac{\mu_0 I}{4\pi d} (\sin \theta_1 + \sin \theta_2)\)
• C. \(\frac{\mu_0 I}{4\pi d} (\cos \theta_1 - \cos \theta_2)\)
• D. \(\frac{\mu_0 I}{4\pi d} (\cos \theta_1 + \cos \theta_2)\)

Hint:

The Biot-Savart law is fundamental for calculating the magnetic field due to current-carrying elements. For a straight wire, the field depends on the angles formed between the wire and the point where the field is being calculated.