Apply Kepler's Third Law: \(T^2 \propto r^3\). Set up a ratio comparing Mars and Mercury: \( \left( \frac{T_{Me}}{T_M} \right)^2 = \left( \frac{r_{Me}}{r_M} \right)^3 \). Substitute the given values and solve for \(T_{Me}\). Remember that \(r_{Me}/r_M = 1/1.5 = 2/3\).