Question:medium

The quantum numbers of four electrons are given below:
I. \( n = 4; l = 2; m_l = -2; s = -\frac{1}{2} \)
II. \( n = 3; l = 2; m_l = 1; s = +\frac{1}{2} \)
III. \( n = 4; l = 1; m_l = 0; s = +\frac{1}{2} \)
IV. \( n = 3; l = 1; m_l = -1; s = +\frac{1}{2} \)
The correct decreasing order of energy of these electrons is:

Updated On: Nov 26, 2025
  • IV > II > III > I
  • I > III > II > IV
  • III > I > II > IV
  • I > II > III > IV