Question

The potential energy of a particle moving along the x-direction varies as:
\[ V = \frac{Ax^2}{\sqrt{x} + B} \]
The dimensions of \(\frac{A^2}{B}\) are:

• A. \(\left[ M^{\frac{3}{2}} L^{\frac{1}{2}} T^{-3} \right]\)
• B. \(\left[ M^{\frac{1}{2}} L T^{-3} \right]\)
• C. \(\left[ M^2 L^{\frac{1}{2}} T^{-4} \right]\)
• D. \(\left[ ML^2T^{-4} \right]\)