Question:medium
The number of lone pair of electrons and the hybridization of Xenon (Xe) in XeOF$_2$ are
The number of lone pair of electrons and the hybridization of Xenon (Xe) in XeOF$_2$ are
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Key Points:
Central atom: Xe (8 valence e$^-$).
Bonded atoms: 1 O (double bond), 2 F (single bonds).
Electrons used in bonds: 2 (for =O) + 2$\times$1 (for F) = 4.
Non-bonding electrons: 8 - 4 = 4.
Lone pairs: 4 / 2 = 2.
Steric Number (SN) = (Bonded atoms) + (Lone pairs) = 3 + 2 = 5.
Hybridization for SN=5 is sp$^3$d.
Key Points:
Central atom: Xe (8 valence e$^-$).
Bonded atoms: 1 O (double bond), 2 F (single bonds).
Electrons used in bonds: 2 (for =O) + 2$\times$1 (for F) = 4.
Non-bonding electrons: 8 - 4 = 4.
Lone pairs: 4 / 2 = 2.
Steric Number (SN) = (Bonded atoms) + (Lone pairs) = 3 + 2 = 5.
Hybridization for SN=5 is sp$^3$d.
Updated On: Nov 28, 2025
- 1, sp$^3$
- 1, dsp$^2$
- 3, dsp$^3$
- 2, sp$^3$d
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Identify the correct orders against the property mentioned:
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