Question

The number of atoms in 0.1 mole of a triatomic gas will be (NA = \( 6.02 \times 10^{23} \)):

• A. \( 1.800 \times 10^{22} \)
• B. \( 6.026 \times 10^{22} \)
• C. \( 1.806 \times 10^{23} \)
• D. \( 3.600 \times 10^{23} \)

Hint:

To find the total number of atoms, multiply: \[ \text{Moles of gas} \times N_A \times \text{Atoms per molecule} \] For triatomic gases, multiply by 3.