Question

The minimum force required to start pushing a body up a rough (having coefficient of friction \( \mu \)) inclined plane is \( F_1 \), while the minimum force needed to prevent it from sliding is \( F_2 \). If the inclined plane makes an angle \( \theta \) with the horizontal such that \( \tan\theta = 2\mu \), then the ratio \( \frac{F_1}{F_2} \) is:

• A. 4
• B. 1
• C. 2
• D. 3

Hint:

When dealing with friction and inclined planes, remember the components of gravitational force acting along and perpendicular to the incline, and use the frictional force \( F_{\text{friction}} = \mu N \) to solve problems.