Question

The maximum area of a right-angled triangle with hypotenuse \( h \) is: (a) \( \frac{h^2}{2\sqrt{2}} \)

• A. \(\frac{h^2}{2{\sqrt{2}}}\)
• B. \( \frac{h^2}{2} \)
• C. \( \frac{h^2}{\sqrt{2}} \)
• D. \( \frac{h^2}{4} \)

Hint:

For a right-angled triangle with hypotenuse \( h \), the maximum area occurs when \( \theta = 45^\circ \), leading to the formula \( A = \frac{h^2}{4} \).