Question:medium
The amount of glucose required to prepare 250 mL of \( \frac{M}{20} \) aqueous solution is:
(Molar mass of glucose: 180 g mol-1)
The amount of glucose required to prepare 250 mL of \( \frac{M}{20} \) aqueous solution is:
(Molar mass of glucose: 180 g mol-1)
(Molar mass of glucose: 180 g mol-1)
Updated On: Nov 26, 2025
- 2.25 g
- 4.5 g
- 0.44 g
- 1.125 g
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