Question:medium
Let \( x - y = 0 \) and \( x + y = 1 \) be two perpendicular diameters of a circle of radius \( R \). The circle will pass through the origin if \( R \) is equal to:
Let \( x - y = 0 \) and \( x + y = 1 \) be two perpendicular diameters of a circle of radius \( R \). The circle will pass through the origin if \( R \) is equal to:
Show Hint
The intersection of perpendicular diameters gives the center of the circle. The distance from the center to any point on the circle (including the origin, if it lies on the circle) is the radius.
Updated On: Nov 28, 2025
- \( \frac{1}{2} \)
- \( \frac{1}{\sqrt{2}} \)
- \( \frac{1}{\sqrt{3}} \)
- \( \frac{1}{3} \)
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