Question

Let the acute angle bisector of the two planes \( x - 2y - 2z + 1 = 0 \) and \( 2x - 3y - 6z + 1 = 0 \) be the plane \( P \). Then which of the following points lies on \( P \)?

• A. \( (3, 1, -\frac{1}{2}) \)
• B. \( (-2, 0, -\frac{1}{2}) \)
• C. \( (0, 2, -4) \)
• D. \( (4, 0, -2) \)

Hint:

When solving for points on the angle bisector of two planes, ensure you correctly apply the formula for the angle bisector and test the points by substituting their coordinates.