Question:medium
In \(\triangle ABC\), coordinates of \(A\) are \((1, 2)\), and the equations of the medians through \(B\) and \(C\) are \(x + y = 5\) and \(x = 4\), respectively. Then the midpoint of \(BC\) is:
In \(\triangle ABC\), coordinates of \(A\) are \((1, 2)\), and the equations of the medians through \(B\) and \(C\) are \(x + y = 5\) and \(x = 4\), respectively. Then the midpoint of \(BC\) is:
Updated On: Nov 28, 2025
- \(\left(5, \frac{1}{2}\right)\)
- \(\left(\frac{11}{2}, 1\right)\)
- \(\left(11, \frac{1}{2}\right)\)
- \(\left(\frac{11}{2}, \frac{1}{2}\right)\)
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