Question:medium
In the given circuit, \(E_1 = E_2 = E_3 = 2V\) and \(R_1 = R_2 = 4\Omega\), then the current flowing through the branch AB is:
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In the given circuit, \(E_1 = E_2 = E_3 = 2V\) and \(R_1 = R_2 = 4\Omega\), then the current flowing through the branch AB is:
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Use Kirchhoff’s Laws to analyze complex circuits efficiently.
Updated On: Nov 26, 2025
- \(0\)
- \(2A\) from A to B
- \(2A\) from B to A
- \(5A\) from B to B
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