Question

If $ y = \tan^{-1}\left(\frac{2x}{1 - x^2}\right) $, then $ \frac{dy}{dx} $ is:

• A. \( \frac{2}{1 + x^2} \)
• B. \( \frac{1 - x^2}{1 + x^2} \)
• C. \( \frac{2}{(1 - x^2)^2} \)
• D. \( \frac{2}{1 - x^2} \)

Hint:

Key Fact: Use inverse trigonometric identities to simplify before differentiating.