Question

If the curve \(y^2 = 6x\) and \(9x^2 + by^2 = 16\) intersect each other at right angles, then the value of \(b\) is:

• A. \(\frac{9}{2}\)
• B. \(4\)
• C. \(6\)
• D. \(\frac{7}{2}\)

Hint:

The orthogonality condition \(m_1 \cdot m_2 = -1\) is critical for perpendicular intersections.