Question:medium

How many moles of electrons are required for the reduction of 1 mole of \( \mathrm{Cr^{3+}} \) to \( \mathrm{Cr^0} \) (s)?

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For reduction reactions, the number of electrons required is equal to the difference in oxidation states multiplied by the number of moles of the substance.
Updated On: Nov 26, 2025
  • 1 mole of \( e^- \)
  • 2 moles of \( e^- \)
  • 3 moles of \( e^- \)
  • None of these